Friday, 16 January 2015

Weekend Food for Thought: Pondering over Primes 02

Given that 74 088 000 = 2^m X 3^3 X 7^3 X 5^n, find the values of m and n.


Key in the values of m and n under Comments

Remember to sign off with your group number.
Complete this by 18 January 2015.

5 comments:

  1. m is 6, n is 3.
    The is how did i do it: 1st take 74088000÷ by 3^3 and 7^3. We get 8000. then i divided 8000 using the factor tree using only the nos. 2 and 5.

    Group 2

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