No. If "x" is an even number, it means that -5 will become a positive number after multiplication, making it THE SAME AS "(-5x) squared by 2" But, if it "x" is an odd number, it means that -5 would still be a negative number, making it SMALLER than "5x squared by 2".
For example, in 5x squared by 2 and (-5x) squared by 2, x = 2, then 5x squared by 2 would be 100, and (-5x) squared by 2 would also be 100, thus making them equal.
If x is less than 0, 5x to the power of 2 will be positive, and -5x to the power of two will be negative.Hence 5x to the power of 2 could be larger than -5x to the power of 2.
If x is equal to 0, both will be the same.
I do not agree. If X=2, 5 x X=10. Its square root is positive 100. (-5X) would be -5 x X= -10. The square root of -10 is 100. The two numbers do not always have to be different.
No. Minus squared is positive. If x is 1, (-5x)2 is the same as 5x2.
X is 0 she said that it is always smaller than but if they represent x as 0, both would be 0 which would be equal not smaller
if x is 0
This comment has been removed by the author.
wronglets say x is -20 then 5x2 is equal to 20but -5x2 is equal to 100
x is 0
If x is a negative, then 5x^2 is greater than(-5x)^2.If x is a positive , then 5x ^2 is smaller than (-5x)^2If x is 0, then they are equal.That depends on the kind of integers are substituted for x.
NO. if x is 0, the whole sum will be equal to 0. so they can be equal and 5x square is not smaller then (-5x) square
No because if x is zero both of the numbers will be the same. If x is 1 both of the numbers can also be the same
5x^2 can be the same as (-5x)^2. When x = 0, 5(0)^2 is 0 and (-5(0))^2 is 0 as well.
If x=1, both would be the same. So the number is not always smaller than the other.
no. it really depends. if x is 0 then the ans is all 0. if x is bigger than 0 then (-5x)^2 is bigger than 5x^2. if x is smaller than 0 the 5x^2 is bigger than (-5x)^2
Alex inspired me with his public speech
yes. No matter what number is put in, the ans for 5x2 is always smaller
No.x*x*5 and -5*x(-5*x) are the simplified values.If we cancel them out, there is *x and *(-5)*x left, whereas *(-5)*x is bigger.Therefore, the answer is wrong.
5x^2 will be smaller than (-5x)^2 if "x" is a positive number, but if "x" is a negative number, 5x^2 will be bigger than (-5x)^2. However' if "x" is 0, They will be the same.
If x = 0, the answer of the equation is equal. Therefore it is NOT ALWAYS smaller.